思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
In 1992, in a small shop in British Columbia, a sign maker named Blair Gran stared at a wall full of half-finished jobs and felt something click. Sign-making was treated like a commodity — orders in, banners out — but as thousands of signs came through his shop, he couldn’t help but notice the difference between the good ones and the bad ones. He could see that every sign that left his shop was either helping a business get noticed, or letting it disappear in plain sight.
，这一点在一键获取谷歌浏览器下载中也有详细论述
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luajit-2.1.1748459687-2.fc42.x86_64